NIMCET 2027 Age Previous Year Questions (PYQs) – Page 2 of 2
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Showing 19 questions
There are four brothers Alan, Bob, Carl and Dave. Dave is two years older than Bob. Bob is one year
younger than Carl. Alan, who is 34, is two years younger than Carl. Who is the oldest?
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Solution
When Rajeev was born his father was 32 years older than his brother and his mother was 25 years
older than his.sister. If Rajeev's brother is 6 years older than Rajeev and his mother is 3 years
younger than his father, how old was Rajeev's sister when he was born?
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Solution
A person's present age is two-fifth of the age
of his mother. After 8 years, he will be one
half of the age of his mother. What is the
present age of the mother?
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Solution
Let present age of mother is x,
then present age of his som = $\frac{2x}{5}$
After 8 year
son's age$\frac{2x}{5}+8$
mother's age =$x+8$
And given that son's age is $\frac{1}{2}$ time of mother's
$\frac{2x}{5}+8=\frac{1}{2}(x+8)$
Hence ,present age of mother is 40
At an IIM entrepreneurship summit, two young founders - Karan and Deepak -
introduced their startup. In their quirky opening, they said: "The product of our ages is 240.
And just like in our startup strategy, twice Deepak's age is 4 years more than Karan's age."
How old was Deepak two years ago?
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Solution
Let Karan’s present age = $K$ years
Let Deepak’s present age = $D$ years
Given:
$K \times D = 240$
and $2D = K + 4 \Rightarrow K = 2D - 4$
Substitute in the first equation:
$(2D - 4)D = 240$
$\Rightarrow 2D^2 - 4D - 240 = 0$
$\Rightarrow D^2 - 2D - 120 = 0$
Solving: $D = \dfrac{2 + \sqrt{484}}{2} = \dfrac{2 + 22}{2} = 12$
Deepak’s present age = $12$ years
Two years ago = $12 - 2 = \mathbf{10}$ years
✅ Final Answer: $10$ years
Let Deepak’s present age = $D$ years
Given:
$K \times D = 240$
and $2D = K + 4 \Rightarrow K = 2D - 4$
Substitute in the first equation:
$(2D - 4)D = 240$
$\Rightarrow 2D^2 - 4D - 240 = 0$
$\Rightarrow D^2 - 2D - 120 = 0$
Solving: $D = \dfrac{2 + \sqrt{484}}{2} = \dfrac{2 + 22}{2} = 12$
Deepak’s present age = $12$ years
Two years ago = $12 - 2 = \mathbf{10}$ years
✅ Final Answer: $10$ years
Radha is twice as old as Rita was 2 years ago. If difference between their ages is 2 years, how old is Radha today?
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Solution
Ten years ago, Ram was twice as old as Shyam. Ten years from now, the ratio of their ages
will be 3:2.
What is Ram's present age?
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Solution
Let Ram’s present age = $R$ years
Let Shyam’s present age = $S$ years
Ten years ago: $R - 10 = 2(S - 10)$
⇒ $R = 2S - 10$
Ten years from now: $\dfrac{R + 10}{S + 10} = \dfrac{3}{2}$
⇒ $2R + 20 = 3S + 30$
⇒ $2R = 3S + 10$
Substitute $R = 2S - 10$ into it:
$2(2S - 10) = 3S + 10$
⇒ $4S - 20 = 3S + 10$
⇒ $S = 30$
Then $R = 2(30) - 10 = 50$
✅ Final Answer: Ram’s present age = 50 years
Let Shyam’s present age = $S$ years
Ten years ago: $R - 10 = 2(S - 10)$
⇒ $R = 2S - 10$
Ten years from now: $\dfrac{R + 10}{S + 10} = \dfrac{3}{2}$
⇒ $2R + 20 = 3S + 30$
⇒ $2R = 3S + 10$
Substitute $R = 2S - 10$ into it:
$2(2S - 10) = 3S + 10$
⇒ $4S - 20 = 3S + 10$
⇒ $S = 30$
Then $R = 2(30) - 10 = 50$
✅ Final Answer: Ram’s present age = 50 years
Five years ago, $A$ was three times as old as $B$. Now, $A$ is twice as old as $B$. What is $A$'s current age in years?
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Solution
Let the present age of $B$ be $x$ years.
Then present age of $A$ is:
$2x$
Five years ago,
Age of $A=2x-5$
Age of $B=x-5$
According to the question:
$2x-5=3(x-5)$
$2x-5=3x-15$
$3x-2x=15-5$
$x=10$
So, present age of $A$ is:
$2x=2(10)=20$
My mother is twice as old as my brother. I am five years younger to my brother but
three years older to my sister. If my sister is twelve years of age, how old is
my mother?
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Solution
John is 20 years older than Steve. In 10 years, Steve's age will be half of that of John. What is the present age of Steve?
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Solution
Let the age of Steve be “x” then the age of John is x + 20 after 10 years Steve age be (x + 10), John's age is x+ 30. Now,
2(x + 10) = x +3
Therefore, x = 10
NIMCET 2027
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and More.
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