From the column addition,
Since the 5th column gives $S+c_4=10c_5$ and $S\neq0$, we must have $S=9,\ c_4=1,\ c_5=1$.
Then $H$ cannot be $9$, so the only valid case is $H=0$.
From last column $W+c_5=L \Rightarrow L=W+1$.
From units column $L+N=S \Rightarrow N=9-L$.
Solving remaining constraints gives:
$S=9,\ T=7,\ I=1,\ L=6,\ W=5,\ H=0,\ N=3,\ M=4$
So,
$STILL=97166$
$WITHIN=517013$
$LIMITS=614179$
Check:
$97166+517013=614179$ ✅
Final Answer:
Correct relation is $97166+517013=614179$.