NIMCET 2027 Syllogism Previous Year Questions (PYQs) – Page 1 of 4
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Showing 35 questions
If the statements “All chickens are birds”, “Some chickens are hens” and “Female birds lay
eggs”, are all facts, then which of the following must also be a fact?
I. All birds lay eggs
I. All birds lay eggs
II. Some hens are birds
III. Some chickens are not hens
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Solution
If there are no dancers that aren’t slim and no singers
that aren’t dancers, then which statements are always
true?
Choose the correct answer
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Solution
Read the conclusion and then decide which of the given conclusions logically follows from the
two given statements, (i) and (ii) disregarding commonly known facts.
Statements:
(i) No woman teacher can play.
(ii) Some woman teachers are athletes.
Conclusions:
I. Male athletes can play.
II. Some athletes can play
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Solution
Statements:
Most teachers are boys.
Some boys are students.
Conclusion:
I. Some students are boys.
II. Some teachers are students.
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Solution
Statement
No table is chair
Not a single chair is stand
Every stand is statue
Conclusion
1. Some statue which are stand are table as well
2. Some statue are not chair
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Solution
Statements:
All jewels are rings.
Some rings are necklaces.
Some cakes are jewels.
Conclusions:
I. Some necklaces are jewels.
II. Some rings are cakes.
III. No jewel is necklace.
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Solution
From “Some cakes are jewels” and “All jewels are rings” ⇒ those cakes are rings ⇒ “Some rings are cakes” is definitely true ⇒ Conclusion II follows.
From “Some rings are necklaces” and “All jewels are rings” we cannot be sure that the necklaces are jewels, so I does not follow.
“No jewel is necklace” is also not forced; it might be true or false, so III does not follow.
So, only II follows.
Statements:
All actors are writers.
Some writers are dancers.
All poets are writers.
Conclusions:
I. All actors are poets.
II. Some dancers are writers.
III. Some dancers are actors.
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Solution
From “Some writers are dancers” we can say some dancers are writers ⇒ Conclusion II follows.
Nothing links “actors” and “poets”, so I does not follow.
We are never told that any of the dancers are actors, so III does not follow.
So, only II follows.
Statements:
Some trees are branches.
All buds are branches.
All flowers are trees.
Conclusions:
I. Some branches are buds.
II. Some trees are flowers.
III. Some buds are trees.
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Solution
From “All buds are branches” and assuming buds exist, we get some branches are buds ⇒ I follows.
From “All flowers are trees” and assuming flowers exist, we get some trees are flowers ⇒ II follows.
There is no link given between buds and trees, so we cannot say “some buds are trees” ⇒ III does not follow.
So, only I and II follow.
Statements:
Some pots are eatables.
All eatables are drinks.
No banana is pot.
Conclusions:
I. Some pots are drinks.
II. All eatables are pots.
III. Some drinks are eatables.
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Solution
Check Conclusion I: “Some pots are drinks.”
We know:
Some pots are eatables.
All eatables are drinks.
So those eatables (which are pots) are definitely drinks.
Hence Some pots are drinks → TRUE
✔ Conclusion I follows.
Check Conclusion II: “All eatables are pots.”
We only know:
Some pots are eatables
But not
All eatables are pots
So this cannot be concluded.
❌ Conclusion II does NOT follow.
Check Conclusion III: “Some drinks are eatables.”
Given:
All eatables are drinks
This directly means:
Eatables ⊂ Drinks → So definitely some drinks are eatables.
✔ Conclusion III follows.
Statements:
(A) Some green are blue
(B) No blue is white
Conclusions:
I) Some blue are green
II) Some white are green
III) Some green are not white
IV) All white are green
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Solution
From (A):
$ \text{Some green are blue} \Rightarrow \text{intersection of green and blue is non–empty} $
So we can also say:
$ \text{Some blue are green} $
Therefore Conclusion I follows.
From (B):
$ \text{No blue is white} \Rightarrow \text{all blue are non–white} $
Combine with (A):
Those objects which are both green and blue are also not white.
So:
$ \text{Some green are not white} $
Therefore Conclusion III also follows.
For II (Some white are green) and IV (All white are green),
nothing in the statements links white to green positively. Both may or may not overlap, so these do not follow.
Hence only I and III are valid.
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