Let tangent be $y=mx+c$, $m>0$.
Tangency with $y^2=4x$ gives $c=\dfrac1m$.
Tangency with the circle gives $|3m-c|=3\sqrt{m^2+1}$.
Solving gives $m=\dfrac1{\sqrt3},\ c=\sqrt3$.
Equation:
$\sqrt3y=x+3$
Answer: $\boxed{\sqrt3y=x+3}$
🎓 NIMCET📅 Year: 2010📚 Mathematics🏷 Conic Section
1
The angle of intersection of the cardioids $r = a(1 + \cos\theta)$ and $r = a(1 - \cos\theta)$ is