| List A (Animals) | List B (Sounds) |
| A. apes | 1. howl |
| B. wolves | 2. gibber |
| C. lambs | 3. squeal |
| D. pigs | 4. bleat |
Case 1: All persons are distinct
For n distinct persons around a round table (rotations same), arrangements = \((n-1)!\).
Here, \(n=9\). So arrangements = \((9-1)! = 8! = \boxed{40{,}320}\).
Case 2: Persons are identical by nationality
If 4 Indians, 3 Americans, and 2 Britishers are considered identical within their groups, then
Arrangements = \[ \frac{(n-1)!}{4!\,3!\,2!} = \frac{8!}{4!\,3!\,2!} = \boxed{140}. \]
Online Test Series, Information About Examination,
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Online Test Series, Information About Examination,
Syllabus, Notification
and More.