Let $\mathbb{N}$ be the set of natural numbers and two functions $f$ and $g$ be defined as $f,g:\mathbb{N}\to\mathbb{N}$ such that
$$
f(n)=
\begin{cases}
\dfrac{n+1}{2}, & \text{if $n$ is odd},\\[4pt]
\dfrac{n}{2}, & \text{if $n$ is even},
\end{cases}
\qquad
g(n)=n-(-1)^n.
$$
Then $f\circ g$ is –
🎓 JEE MAIN📅 Year: 2019📚 Mathematics🏷 Statistics Measures of Central Tendency
3
The outcome of each of 30 items was observed; 10 items gave an outcome $\dfrac{1}{2}-d$ each, 10 items gave outcome $\dfrac{1}{2}$ each and the remaining 10 items gave outcome $\dfrac{1}{2}+d$ each. If the variance of this outcome data is $\dfrac{4}{3}$ then $|d|$ equals :
Let $[x]$ denote the greatest integer less than or equal to $x$. Then
$\displaystyle \lim_{x\to 0}\frac{\tan(\pi\sin^{2}x)+\left(|x|-\sin(x[x])\right)^{2}}{x^{2}}$ :
If $y(x)$ is the solution of the differential equation
$\dfrac{dy}{dx}+\left(\dfrac{2x+1}{x}\right)y=e^{-2x},\ x>0,$ where $y(1)=\dfrac{1}{2}e^{-2}$, then
A square is inscribed in the circle $x^{2}+y^{2}-6x+8y-103=0$ with its sides parallel to the coordinate axes. Then the distance of the vertex of this square which is nearest to the origin is :