Let $S$ be the set of all values of $\lambda$ for which the shortest distance between the lines
$\dfrac{x-\lambda}{0}=\dfrac{y-3}{4}=\dfrac{z+6}{1}$ and $\dfrac{x+\lambda}{3}=\dfrac{y}{-4}=\dfrac{z-6}{0}$ is $13$.
Then $8\Big|\displaystyle\sum_{\lambda\in S}\lambda\Big|$ is equal to:
🎓 JEE MAIN📅 Year: 2023📚 Mathematics🏷 Complex Number
4
If the set $\left\{\operatorname{Re}\!\left(\dfrac{z-\overline{z}+z\overline{z}}{\,2-3z+5\overline{z}\,}\right): z\in\mathbb{C},\ \operatorname{Re}(z)=3\right\}$ is equal to the interval $(\alpha,\beta]$, then $24(\beta-\alpha)$ is equal to:
Let \(\vec{a} = 4\hat{i} + 3\hat{j}\) and \(\vec{b} = 3\hat{i} - 4\hat{j} + 5\hat{k}\).
If \(\vec{c}\) is a vector such that
\[
\vec{c}\cdot(\vec{a}\times\vec{b}) + 25 = 0,\qquad
\vec{c}\cdot(\hat{i}+\hat{j}+\hat{k}) = 4,
\]
and the projection of \(\vec{c}\) on \(\vec{a}\) is \(1\), then the projection of \(\vec{c}\) on \(\vec{b}\) equals:
Let \(K\) be the sum of the coefficients of the odd powers of \(x\) in the expansion of \((1+x)^{99}\).
Let \(a\) be the middle term in the expansion of \(\left(2+\frac{1}{\sqrt{2}}\right)^{200}\).
If \(\displaystyle \frac{\binom{200}{99} \, K}{a} = \frac{2^{\,\ell} \, m}{n}\), where \(m\) and \(n\) are odd numbers, then the ordered pair \((\ell,n)\) is:
🎓 JEE MAIN📅 Year: 2023📚 Mathematics🏷 Straight line
3
The shortest distance between the lines
\[
\frac{x-1}{2}=\frac{y+8}{-7}=\frac{z-4}{5}
\quad\text{and}\quad
\frac{x-1}{2}=\frac{y-2}{1}=\frac{z-6}{-3}
\]
is:
The functions $f$ and $g$ are twice differentiable on $\mathbb{R}$ such that
$f''(x) = g''(x) + 6x$
$f'(1) = 4g'(1) - 3 = 9$
$f(2) = 3g(2) = 12$
Then which of the following is NOT true?