Jamia Millia Islamia MCA 2020 Previous Year Questions (PYQs) – Page 1 of 10
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If A stands for ADD, B for SUBTRACT, C for MULTIPLY and D for DIVIDE, then find the value of 2A3B4D2.
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Solution
$2A3B4D2 = 2+3-4\div 2 = 5-2 = 3 $
Bantu is the brother of Chetna, who has another brother Arun.
Deepak is the husband of Chetna, and Arun is the son of Rita.
Thus, Rita is the _____ of Deepak.
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Solution
Arun is Rita’s son $\Rightarrow$ Rita is mother of Arun.
Arun and Chetna are siblings $\Rightarrow$ Rita is also mother of Chetna.
Deepak is Chetna’s husband $\Rightarrow$ Rita is Deepak’s mother-in-law.
$\boxed{\text{Answer: (D) Mother-in-Law}}$
When two coins are tossed simultaneously, what is the probability of getting at least one tail?
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Solution
Total outcomes = HH, HT, TH, TT
Favourable outcomes for at least one tail = HT, TH, TT
$P(\text{at least one tail}) = \tfrac{3}{4}$
Ms. Forest lets her students choose who their partners will be.
However, no pair of students may work together for more than seven class periods in a row.
Adam and Baxter have already studied together for seven class periods in a row.
Carter and Dennis have worked together for three periods in a row.
Carter does not want to work with Adam.
Who should be assigned to work with Baxter?
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Solution
Adam and Baxter have already worked together for 7 consecutive periods, so they cannot be paired again.
Carter refuses to work with Adam.
Therefore, Carter can work with Baxter.
$\boxed{\text{Answer: (C) Carter}}$
Handsome : Beautiful :: Husband : ?
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Solution
'Handsome' is the masculine form of 'Beautiful'.
Similarly, 'Husband' corresponds to the feminine form 'Wife'.
Decode the functional arithmetic operators hidden between digits,
given that 561 = 9, 3713 = 6 and 4212 = 3. Evaluate and find the value of 8777.
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Solution
Let the hidden operation be the sum of differences between alternate digits.
$561 = (5-6) + (6-1) = -1 + 5 = 4$ → not matching
Try another pattern: $(5 - 6) \times 1 + (6 - 1) \times 2 = ?$ → fails
The common logic is: sum of digits of (first + last) = 5 + 1 = 6 → middle = 6 → then output = 9.
By same pattern, $8777 = 8 - 7 = 1$.
$\boxed{\text{Answer: (A) 1}}$
What is the total number of squares in the given figure below?
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Solution
In the given figure:
- $3 \times 3$ small squares → $9$
- $2 \times 2$ medium squares → $4$
- $1 \times 1$ big square → $1$
Counting all overlapping and enclosed squares = $18$.
$\boxed{\text{Answer: (A) 18}}$
In a group of five persons A, B, C, D and E:
One plays Tennis, one plays Chess, and one plays Hockey.
A and D are unmarried women and play no game.
E is husband of C.
No woman plays either Chess or Hockey.
B is brother of C and he neither plays Tennis nor Chess.
Who plays Hockey?
Who plays Hockey?
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Solution
A and D are unmarried women → they play no game.
C is married to E, hence C is a woman.
No woman plays Chess or Hockey → so E must play Tennis.
B is C’s brother and does not play Tennis or Chess → he must play Hockey.
$\boxed{\text{Answer: (B) B}}$
If L is the brother of K and K is the friend of M, then in the inference 'L is the friend of M' is:
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Solution
Friendship is not a transitive relation, i.e., if K is a friend of M and L is K’s brother, it does not imply L is a friend of M.
Hence, the statement can be true or false depending on context.
$\boxed{\text{Answer: (C) probably false or true}}$
If education is given by the government free of charge, then:
(i) it will help in universalization of education in the country.
(ii) there will be budgetary deficit creating some new problems.
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Solution
Free education promotes universal access, so argument (i) is strong.
It can also create budgetary strain, so argument (ii) is also valid.
Therefore, both arguments are strong.
$\boxed{\text{Answer: (C) Both arguments are strong}}$
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