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A is three times as old as B. C was twice as old as A four years ago. In four years’ time, A will be 31. What are the present ages of B and C?
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Solution
In 4 years A will be $31 \Rightarrow$ now $A=31-4=27$. Given $A=3B \Rightarrow B=27/3=9$. Four years ago $A=23$, so $C=2\times 23=46 \Rightarrow$ now $C=46+4=50$.
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