$AB^{2}=14^{2}+2^{2}=200,\ BC^{2}=(-8)^{2}+6^{2}=100,\ CA^{2}=(-6)^{2}+(-8)^{2}=100$.
Since $BC=CA$ the triangle is isosceles, and $BC^{2}+CA^{2}=AB^{2}$ ⇒ right-angled at $C$.
🎓 Jamia Millia Islamia MCA📅 Year: 2016📚 Mathematics🏷 Straight line
2
If the point $P(x,y)$ is equidistant from $A(a+b,\,b-a)$ and $B(a-b,\,a+b)$, then …
Parallel lines: $2x+6y+c=0$.
Intercept points: $( -\tfrac{c}{2},0)$ and $(0,-\tfrac{c}{6})$.
Distance between them $=\sqrt{\left(\tfrac{c}{2}\right)^{2}+\left(\tfrac{c}{6}\right)^{2}}
=|c|\,\dfrac{\sqrt{10}}{6}$.
Set equal to $10$ ⇒ $|c|=6\sqrt{10}$ ⇒ two values $c=\pm6\sqrt{10}$.
🎓 Jamia Millia Islamia MCA📅 Year: 2016📚 Mathematics🏷 Straight line
They form two pairs of parallel lines with slopes $\pm \dfrac{a}{b}$ (not necessarily perpendicular).
Under unequal scaling they form a rectangle (a square only if $a=b$).
🎓 Jamia Millia Islamia MCA📅 Year: 2016📚 Mathematics🏷 Straight line
2
The area bounded by the lines $y=|x|-1$ and $y=-|x|+1$ is …… square unit.
Total outcomes = $6 \times 6 = 36$.
Favorable outcomes for sum = 7 are $(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)$ → 6 outcomes.
Probability $= \dfrac{6}{36} = \dfrac{1}{6}$.
🎓 Jamia Millia Islamia MCA📅 Year: 2016📚 Mathematics🏷 Probability
1
A single letter is selected at random from the word “JAMIA”. The probability that it is a vowel is …
Probability of 6 on die $= \dfrac{1}{6}$,
Probability of head on coin $= \dfrac{1}{2}$.
Required probability $= \dfrac{1}{6} \times \dfrac{1}{2} = \dfrac{1}{12}$.