Jamia Millia Islamia C Programming Language Previous Year Questions (PYQs) – Page 3 of 5
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Showing 49 questions
Consider the following code segment:
if (n > 0)
for (i = 0; i < 3; i++)
if (array[i] > 0)
printf("%d\n", array[i]);
else
printf("\n n is negative\n");
Here, ‘else’ is paired with which ‘if’?
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Solution
Solution:
In C, **“else” is always paired with the nearest unmatched “if”** (no braces rule).
Here:
- The inner `if (array[i] > 0)` is the **nearest unmatched `if`** before `else`.
So, the `else` is paired with the **second (inner)** `if`.
For this kind of declaration of main() function in a C program ‘copy.C’:
int main(int argc, char *argv[]) { }
and this call of main function at command prompt:
C:\tc\bin>copy file1 file2 file3
What will be the value passed in parameter argc?
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Solution
Solution:
The **argc (argument count)** includes the program name itself.
So the arguments are:
1️⃣ "copy" (program name)
2️⃣ "file1"
3️⃣ "file2"
4️⃣ "file3"
Thus, total arguments = 4.
What is the correct file mode that opens preexisting file in read and write mode?
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Solution
Solution:
- `"r+b"` or `"rb+"` → open **existing file** for both reading and writing (no truncation).
- `"w+b"` or `"wb+"` → open file for reading and writing but **creates/truncates** file.
- `"ab"` → append binary mode.
Hence, the correct mode for **existing file in read-write** is `"r+b"`.
Which C expression correctly represents this statement:
“It decrements pointer p before fetching the character that p points to.”
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Solution
Solution:
- `p--` → post-decrement (use then decrement)
- `--p` → pre-decrement (decrement then use)
Here, we need to **decrement p first**, then fetch the value it points to.
Hence, correct expression: `*--p`
How many times this statement will execute:
for (; *s == *t && *t != '\0'; s++, t++)
if both character pointers ‘s’ and ‘t’ point to the same string “abc”.
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Solution
Solution:
String = "abc" → characters: a, b, c, '\0'
Loop condition:
- Iteration 1: *s = 'a', *t = 'a' → true
- Iteration 2: *s = 'b', *t = 'b' → true
- Iteration 3: *s = 'c', *t = 'c' → true
- Iteration 4: *s = '\0', *t = '\0' → fails because *t != '\0' → false
Hence, loop executes **3 times**.
Which out of these statements is NOT true:
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Solution
Solution:
All three statements (A), (B), and (C) are correct according to C language behavior.
Hence, there is **no incorrect statement**.
Which out of these is NOT the keyword C99 has added in addition to 32 keywords defined by ANSI C?
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Solution
Solution:
C99 added these new keywords:
- `_Bool`
- `inline`
- `restrict`
- `_Complex`
- `_Imaginary`
`register` is an **old ANSI C keyword**, not added in C99.
Which out of these is NOT a valid C version?
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Solution
Solution:
Valid C versions are:
- C89 (ANSI standard, 1989)
- C90 (ISO standard, 1990)
- C99, C11, C17, and C23
There is **no version called C2007 or CIX**.
What will be the output of the statement
printf(3+"goodbye");
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Solution
"goodbye" is a char array; 3 + "goodbye" points to the 4th char → "dbye".
What will be the output of the statements?
int i = 1, j;
j = i-- - -2;
printf("%d", j);
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Solution
i-- uses the old value 1, then i becomes 0. Expression is 1 - (-2) = 3.
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