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The results of a class were declared.
The boy ‘X’ stood 5th in the class.
The girl ‘Y’ was 8th from the last.
The position of the boy ‘Z’ was 6th after ‘X’ and in the middle of ‘X’ and ‘Y’.
The total number of students in the class was:
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Solution
X is 5th from the top → X’s position = 5.
Z is 6th after X → Z’s position = 5 + 6 = 11.
Z is also in the middle of X and Y, so Y’s position from top = 11 + 6 = 17.
Since Y is 8th from last,
Total students = 17 + 8 − 1 = 24.
A class of boys stands in a single line. One boy is 19th in order from both ends. How many boys are there in the class?
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Solution
Total = 19 + 19 − 1 = 37.
In a row, A is in the 11th position from the left and B is in the 10th position from the right.
If A and B interchange their positions, then A becomes 18th from the left.
How many persons are there in the row other than A and B?
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Solution
Let total persons = $n$.
B’s position from right = 10 ⇒ from left = $(n - 9)$.
After interchange, A’s new position = 18 = $(n - 9)$.
So, $n = 27$.
Total persons other than A and B = $27 - 2 = 25$.
In a row of men, Manoj is 30th from the right and Kiran is 20th from the left.
After interchanging their positions, Manoj becomes 35th from the right.
What is the total number of men in the row?
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Solution
Solution:
Total = N.
After swap, Manoj is at Kiran’s old place (20th from left) ⇒ from right = N − 20 + 1 = N − 19.
Given N − 19 = 35 ⇒ N = 54.
A, B, C, D and E when arranged in descending order of their weights from the top, A becomes third, E is between D and A while C and D are not at the top. Who is the second heaviest?
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Solution
Descending order (top = heaviest).
A is 3rd. “E is between D and A” and “D is not at the top”.
So A (3rd) > E > D ⇒ E is 4th, D is 5th.
Remaining top two are B and C, and “C is not at the top”, so C is 2nd and B is 1st.
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