Aspire Faculty ID #11651 · Topic: NIMCET 2024 · Just now
NIMCET 2024

The value of $f(1)$ for $f\Bigg{(}\frac{1-x}{1+x}\Bigg{)}=x+2$ is

Solution

Given:
$$f\left(\frac{1 - x}{1 + x}\right) = x + 2$$

To Find: \( f(1) \)

Let \( \frac{1 - x}{1 + x} = 1 \Rightarrow x = 0 \)

Then, \( f(1) = f\left(\frac{1 - 0}{1 + 0}\right) = 0 + 2 = 2 \)

Answer: $$\boxed{2}$$

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