Aspire Faculty ID #11669 · Topic: NIMCET 2024 · Just now
NIMCET 2024

If three distinct numbers are chosen randomly from the first 100 natural numbers, then the probability that all three of them are divisible by both 2 and 3 is

Solution

✔️ Verified Probability

Total numbers divisible by 6 from 1 to 100: 16

\[ \binom{100}{3} = 161700, \quad \binom{16}{3} = 560 \]

Probability: \[ \frac{560}{161700} = \frac{4}{1155} \]

✅ Final Answer: \(\boxed{\frac{4}{1155}}\)

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