Aspire Faculty ID #11981 · Topic: NIMCET 2025 · Just now
NIMCET 2025

Number of three digit numbers that can be formed using 0, 1, 2, 3 and 5 where these digits are allowed to repeat any number of times, is equal to

Solution

Digits available: 0, 1, 2, 3, 5 (total 5 digits). 
Repetition is allowed. 
 To form a three-digit number: 
 1) The first digit cannot be 0. 
 Possible choices = 1, 2, 3, 5 → 4 choices. 
 2) The second digit can be any of the 5 digits → 5 choices. 
 3) The third digit can also be any of the 5 digits → 5 choices. 

 Total three-digit numbers = $4 \times 5 \times 5 = 100$. 
 Final Answer: 100

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