Aspire Faculty ID #12112 · Topic: CUET 2025 · Just now
CUET 2025

Minimum number of 2:1 Multiplexers required to design a 16:1 Multiplexer is?

Solution

To implement an \(n:1\) multiplexer using only \(2:1\) multiplexers, the minimum number required is:

\[ \text{Number of 2:1 MUX} = n - 1 \]

For \(n = 16\):

\[ 16 - 1 = 15 \]

✅ Therefore, the minimum number of \(2:1\) multiplexers required to design a \(16:1\) multiplexer is: \[ \boxed{15} \]

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