Aspire Faculty ID #13029 · Topic: JEE Main 2022 (25 July Morning Shift) · Just now
JEE Main 2022 (25 July Morning Shift)

Let $ABC$ be a triangle such that $\overrightarrow{BC}=\vec a,\ \overrightarrow{CA}=\vec b,\ \overrightarrow{AB}=\vec c,\ |\vec a|=6\sqrt2,\ |\vec b|=2\sqrt3$ and $\vec b\cdot \vec c=12$. Consider the statements: (S1): $\ \big|\ \vec a\times\vec b+\vec c\times\vec b\ \big| - |\vec c| = 6(2\sqrt2-1)$ (S2): $\ \angle ACB=\cos^{-1}!\left(\sqrt{\tfrac{2}{3}}\right)$ Then

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