Let the point $P(\alpha, \beta)$ be at a unit distance from each of the two lines $L_1 : 3x - 4y + 12 = 0$, and $L_2 : 8x + 6y + 11 = 0$.
If $P$ lies below $L_1$ and above $L_2$, then $100(\alpha + \beta)$ is equal to :
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