Aspire Faculty ID #13081 · Topic: JEE Main 2022 (27 July Morning Shift) · Just now
JEE Main 2022 (27 July Morning Shift)

The area of the smaller region enclosed by the curves $y^2 = 8x + 4$ and $x^2 + y^2 + 4\sqrt{3}x - 4 = 0$ is equal to

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