Aspire Faculty ID #13514 · Topic: JAMIA MILLIA ISLAMIA MCA 2024 · Just now
JAMIA MILLIA ISLAMIA MCA 2024

$\sin(\tan^{-1}x)$, where $|x| < 1$, is equal to

Solution

Let $\theta = \tan^{-1}x \Rightarrow \tan\theta = x$ In right triangle: opposite = $x$, adjacent = $1$ $\Rightarrow \sin\theta = \dfrac{x}{\sqrt{1 + x^2}}$

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