Aspire Faculty ID #13846 · Topic: JAMIA MILLIA ISLAMIA MCA 2021 · Just now
JAMIA MILLIA ISLAMIA MCA 2021

The equation of a circle with origin as centre and passing through the vertices of an equ

Solution

Median of equilateral triangle = $\dfrac{\sqrt{3}}{2} \times \text{side}$ $\Rightarrow 3a = \dfrac{\sqrt{3}}{2} \times \text{side}$ $\Rightarrow \text{side} = 2\sqrt{3}a$ Radius (distance from centre to vertex) = $\dfrac{\text{side}}{\sqrt{3}} = 2a$. Equation: $x^2 + y^2 = (2a)^2 = 4a^2$. $\boxed{\text{Answer: (C) }x^2 + y^2 = 4a^2}$

Previous 10 Questions — JAMIA MILLIA ISLAMIA MCA 2021

Nearest first

Next 10 Questions — JAMIA MILLIA ISLAMIA MCA 2021

Ascending by ID
Ask Your Question or Put Your Review.

loading...