Aspire Faculty ID #13917 · Topic: JAMIA MILLIA ISLAMIA MCA 2020 · Just now
JAMIA MILLIA ISLAMIA MCA 2020

In a family, each daughter has the same number of brothers as she has sisters, and each son has twice as many sisters as he has brothers. How many sons are there in the family?

Solution

Let number of sons = $s$, and number of daughters = $d$. For a daughter: number of brothers = $s$, number of sisters = $d - 1$ ⇒ $s = d - 1$ For a son: number of sisters = $d$, number of brothers = $s - 1$ ⇒ $d = 2(s - 1)$ Solving: $s = d - 1$ $d = 2s - 2$ Substitute: $s = (2s - 2) - 1 ⇒ s = 3$.

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