Aspire Faculty ID #13948 · Topic: JAMIA MILLIA ISLAMIA MCA 2020 · Just now
JAMIA MILLIA ISLAMIA MCA 2020

The equation of the normal to the curve $y = \sin x$ at $(0, 0)$ is…….

Solution

Given $y = \sin x$, then $\dfrac{dy}{dx} = \cos x$. At $(0, 0)$, slope of tangent $= \cos 0 = 1$. Therefore, slope of normal $= -1$. Equation: $y - 0 = -1(x - 0)$ → $x + y = 0$. $\boxed{\text{Answer: (C) } x + y = 0}$
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