Aspire Faculty ID #14043 · Topic: JAMIA MILLIA ISLAMIA MCA 2019 · Just now
JAMIA MILLIA ISLAMIA MCA 2019

The vertices of a parallelogram $ABCD$ are $A(3,-1,2)$, $B(1,2,-4)$ and $C(-1,1,2)$. The fourth vertex $D$ is:

Solution

In a parallelogram, $A+C=B+D \Rightarrow D=A+C-B$. $D=(3,-1,2)+(-1,1,2)-(1,2,-4)=(1,-2,8)$.

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