A five digit number divisible by 3 using digits 0, 1, 2, 3, 4, 5 is to be made without repetition. Find of such word.

Digits available: {0,1,2,3,4,5}. 

Sum of all six = 15 divisible by 3.
To make a 5-digit number divisible by 3, exclude one digit whose value 0, i.e., exclude 0 or 3.

• Exclude 0 → use {1,2,3,4,5}: all 5! = 120 numbers (no leading-zero issue).

• Exclude 3 → use {0,1,2,4,5}: total 5! − 4! (leading 0) = 120 − 24 = 96.

Total = 120 + 96 = 216