Aspire Faculty ID #15095 · Topic: JAMIA MILLIA ISLAMIA MCA 2018 · Just now
JAMIA MILLIA ISLAMIA MCA 2018

If $y = a\log|x| + bx^2 + x$ has extreme values at $x=-1$ and $x=-2$, then

Solution

From $y'=a/x + 2bx + 1=0$ → solving gives $a=2,\ b=-\tfrac{1}{2}$.

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