Aspire Faculty ID #15122 · Topic: JAMIA MILLIA ISLAMIA MCA 2018 · Just now
JAMIA MILLIA ISLAMIA MCA 2018

If $\sin t = \dfrac{1}{5}$ and $0 < t < \dfrac{\pi}{2}$, then $\cos(4t)$ = ?

Solution

$\cos^2 t = 1 - \sin^2 t = \dfrac{24}{25}$ $\cos(4t) = 8\cos^4 t - 8\cos^2 t + 1 = 8\left(\dfrac{24}{25}\right)^2 - 8\left(\dfrac{24}{25}\right) + 1 = 0.6928$
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