Aspire Faculty ID #15174 · Topic: JAMIA MCA 2017 · Just now
JAMIA MCA 2017

Let $f:\mathbb{R}\to\mathbb{R},\; g:\mathbb{R}\to\mathbb{R}$ be given by $f(x)=2x-3$ and $g(x)=x/2$. Then $(f\circ g)^{-1}(x)$ is equal to

Solution

$(f\circ g)(x)=f(x/2)=x-3$. Its inverse solves $y=x-3\Rightarrow x=y+3$, so $(f\circ g)^{-1}(x)=x+3$.

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