Aspire Faculty ID #15181 · Topic: JAMIA MCA 2017 · Just now
JAMIA MCA 2017

For which value of $x$, $\left(\dfrac{1+i}{1-i}\right)^{x}=1$ ?

Solution

$\dfrac{1+i}{1-i}=i$. So $i^{x}=1\Rightarrow x\equiv0\pmod4$. Only $68$ is a multiple of $4$.

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