Aspire Faculty ID #15187 · Topic: JAMIA MCA 2017 · Just now
JAMIA MCA 2017

The minimum value of $3\cos\theta+4\sin\theta+10$ is equal to …

Solution

$R=\sqrt{3^2+4^2}=5$. Min$(3\cos\theta+4\sin\theta)=-5$. So min total $= -5+10=5$.

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