Aspire Faculty ID #15191 · Topic: JAMIA MCA 2017 · Just now
JAMIA MCA 2017

If $y=\cos^{-1}x$ and $z=\sin^{-1}\!\sqrt{1-x^{2}}$, then $\dfrac{dy}{dz}$ equals …

Solution

For $x\in[-1,1]$, $\sqrt{1-x^2}=\sin(\cos^{-1}x)=\sin y$. Thus $z=\sin^{-1}(\sin y)$, so $z=y$ (up to piecewise sign); hence $\dfrac{dy}{dz}=1$.

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