Aspire Faculty ID #15265 · Topic: JAMIA MCA 2016 · Just now
JAMIA MCA 2016

$\displaystyle \int \sqrt{x}e^{\sqrt{x}}dx$ is equal to …

Solution

Let $t=\sqrt{x}$, $dx=2t\,dt$. Then $\int 2t^{2}e^{t}dt=2e^{t}(t^{2}-2t+2)+C$. Substitute $t=\sqrt{x}$ ⇒ $(2x-4\sqrt{x}+4)e^{\sqrt{x}}+C$.

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