Aspire Faculty ID #15276 · Topic: JAMIA MCA 2016 · Just now
JAMIA MCA 2016

If $m^{\text{th}}$ term of an A.P. is $n$ and $n^{\text{th}}$ term is $m$, then its $10^{\text{th}}$ term is …

Solution

Let first term $a$, common difference $d$. $a+(m-1)d=n \quad\text{and}\quad a+(n-1)d=m$. Subtract: $(m-n)d=n-m \Rightarrow d=-1$. Then $a=n+(m-1)=m+n-1$. $t_{10}=a+9d=(m+n-1)+9(-1)=m+n-10$.
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