Aspire Faculty ID #15282 · Topic: JAMIA MCA 2016 · Just now
JAMIA MCA 2016

The number of arrangements of the letters of the word BANANA in which two N’s do not appear adjacently is …

Solution

Total letters = 6 (B, A, N, A, N, A). Total arrangements = $\dfrac{6}{32} = 60$. If two N’s are together, treat NN as one letter → letters = (NN, B, A, A, A). Arrangements = $\dfrac{5}{3} = 20$. Hence, required = $60 - 20 = 40$.

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