Aspire Faculty ID #15295 · Topic: JAMIA MCA 2016 · Just now
JAMIA MCA 2016

If $y=(x^{x})^{x}$, then $\dfrac{dy}{dx}$ is …

Solution

$(x^{x})^{x}=x^{x^{2}}=e^{x^{2}\ln x}$. $\Rightarrow \dfrac{y'}{y}=2x\ln x+x\ \Rightarrow\ y'=y(x+2x\ln x)=xy+2xy\log x$.

Previous 10 Questions — JAMIA MCA 2016

Nearest first

Next 10 Questions — JAMIA MCA 2016

Ascending by ID
Ask Your Question or Put Your Review.

loading...