Aspire Faculty ID #15324 · Topic: JAMIA MCA 2016 · Just now
JAMIA MCA 2016

If $(27)_5 = 141$, then the missing digit is …

Solution

$(2x7)_8 = 141_{10} \Rightarrow 2\times8^2 + x\times8 + 7 = 141$. $128 + 8x + 7 = 141 \Rightarrow 8x = 6 \Rightarrow x = \dfrac{6}{8}=0.75$. But $x$ must be a digit (integer), so $x=2$.

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