Aspire Faculty ID #15460 · Topic: MAH MCA CET 2025 (Shift 1) · Just now
MAH MCA CET 2025 (Shift 1)

Find the distance from the eye at which a coin of $2\ \text{cm}$ diameter should be held so as to conceal the full moon whose angular diameter is $31'$.

Solution

Small–angle $\theta\ (\text{radians}) \approx \dfrac{\text{diameter}}{\text{distance}}$. $\theta = 31' = \dfrac{31\pi}{180\times60}$. $d = \dfrac{0.02}{\theta} = \dfrac{0.02\times10800}{31\pi} \approx 2.217\ \text{m}$.

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