Aspire Faculty ID #15493 · Topic: MAH MCA CET 2025 (Shift 1) · Just now
MAH MCA CET 2025 (Shift 1)

A man travels $2,\text{km}$ to the north and turns east and travels $10,\text{km}$, and again he turns north and travels $3,\text{km}$ and again turns to the east and travels $2,\text{km}$. How far is he from the starting point?

Solution

Total east $=10+2=12$, total north $=2+3=5$. Distance $=\sqrt{12^{2}+5^{2}}=\sqrt{144+25}=\sqrt{169}=13,\text{km}$.

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