Aspire Faculty ID #16205 · Topic: NIMCET 2011 · Just now
NIMCET 2011

$ \text{If } B = -A^{-1}BA,\ \text{then } (A+B)^{2} = $

Solution

From $ B = -A^{-1}BA $, multiply both sides by $A$: $ BA = -BA $ So $ BA = 0 $. Then $ (A+B)^{2} = A^{2} + AB + BA + B^{2} = A^{2} + AB + 0 + B^{2} $

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