Aspire Faculty ID #16317 · Topic: NIMCET 2010 · Just now
NIMCET 2010

Area between $y = 2 - x^2$ and $y = x^2$

Solution

Solve intersection: $2 - x^2 = x^2$ $2x^2 = 2$ $x^2 = 1$ → $x = -1,\ 1$ Area = $\int_{-1}^{1} [(2 - x^2) - x^2] dx$ $= \int_{-1}^{1} (2 - 2x^2) dx$ $= 2\int_{-1}^{1} (1 - x^2) dx$ Compute: $\int_{-1}^{1} 1 dx = 2$ $\int_{-1}^{1} x^2 dx = \frac{2}{3}$ Area = $2(2 - \frac{2}{3}) = \frac{8}{3}$

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