Aspire Faculty ID #16419 · Topic: NIMCET 2009 · Just now
NIMCET 2009

A set contains $(2n+1)$ elements. If the number of subsets that contain at most $n$ elements is $4096$, then the value of $n$ is:

Solution

For odd number of elements, 
$\displaystyle \sum_{k=0}^{n} \binom{2n+1}{k} = 2^{2n}$ 
Given: $2^{2n} = 4096 = 2^{12}$ 
So, $2n = 12 \Rightarrow n = 6$

Previous 10 Questions — NIMCET 2009

Nearest first

Next 10 Questions — NIMCET 2009

Ascending by ID
Ask Your Question or Put Your Review.

loading...