Aspire Faculty ID #16426 · Topic: NIMCET 2009 · Just now
NIMCET 2009

If $a + b + c \neq 0$, the system of equations: $(b+c)(y+z) - ax = b - c$ $(c+a)(z+x) - by = c - a$ $(a+b)(x+y) - cz = a - b$ has:

Solution

This is a symmetric linear system. 
Solving gives the unique solution: 
 $x = y = z = 0$ 
 Since $a+b+c \neq 0$, determinant $\neq 0$ → unique solution.

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