Aspire Faculty ID #16557 · Topic: NIMCET 2008 · Just now
NIMCET 2008

A pair of unbiased dice is rolled together till a sum of either $5$ or $7$ is obtained. The probability that $5$ comes before $7$ is

Solution

$P(5)=\dfrac4{36}$, $P(7)=\dfrac6{36}$ Required probability $=\dfrac{P(5)}{P(5)+P(7)}=\dfrac4{10}=\dfrac25$

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