Aspire Faculty ID #17969 · Topic: JEE Main 2026 (22 January Evening Shift) · Just now
JEE Main 2026 (22 January Evening Shift)

If $X=\begin{bmatrix}x\\y\\z\end{bmatrix}$ is a solution of $AX=B$, where $\text{adj }A=\begin{bmatrix}4&2&2\\-5&0&5\\1&-2&3\end{bmatrix}$ and $B=\begin{bmatrix}4\\0\\2\end{bmatrix}$, then $x+y+z$ is equal to:

Solution

Using $A^{-1}=\dfrac{adjA}{|A|}$ and $AX=B$ → $X=\dfrac{adjA\cdot B}{|A|}$. Compute gives sum $=2$

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