Aspire Faculty ID #18003 · Topic: JEE Main 2026 (23 January Morning Shift) · Just now
JEE Main 2026 (23 January Morning Shift)

The value of $\dfrac{{}^{100}C_{50}}{51} + \dfrac{{}^{100}C_{51}}{52} + \cdots + \dfrac{{}^{100}C_{100}}{101}$ is:

Solution

$S = \sum_{r=50}^{100} \dfrac{{}^{100}C_r}{r+1}$ $= \sum_{r=50}^{100} \dfrac{1}{101} \cdot \dfrac{r+1}{r+1} \cdot {}^{100}C_r$ $= \dfrac{1}{101} \sum_{r=50}^{100} {}^{101}C_{r+1}$ $= \dfrac{1}{101} \sum_{r=51}^{101} {}^{101}C_r$ $= \dfrac{1}{101} \cdot \dfrac{2^{101}}{2}$ $= \dfrac{2^{100}}{101}$

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