Aspire Faculty ID #18015 · Topic: JEE Main 2026 (23 January Evening Shift) · Just now
JEE Main 2026 (23 January Evening Shift)

Consider two sets $A = {x \in \mathbb{Z} : |x - 3| - 3 \le 1}$ and $B = {x \in \mathbb{R} - {1,2} : \dfrac{(x-2)(x-4)}{x-1}\log_e(|x-2|) = 0}$ Then the number of onto functions $f : A \to B$ is equal to:

Solution

$|x - 3| - 3 \le 1$

$\Rightarrow |x - 3| \le 4$

$\Rightarrow -1 \le x - 3 \le 4$

$\Rightarrow 2 \le x \le 7$

$A = {-1,0,1,5,6,7}$

For $B$

$\dfrac{(x-2)(x-4)}{x-1}\log_e(|x-2|) = 0$

$\Rightarrow x = 2, 4$ or $|x-2| = 1 \Rightarrow x = 3$

$B = {3,4}$

Number of onto functions

$= 2^6 - 2 = 62$

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