Aspire Faculty ID #18040 · Topic: JEE Main 2026 (24 January Morning Shift) · Just now
JEE Main 2026 (24 January Morning Shift)

Let $\vec a = 2\hat i + \hat j - 2\hat k,; \vec b = \hat i + \hat j$ and $\vec c = \vec a \times \vec b$. Let $\vec d$ be a vector such that $|\vec d - \vec a| = \sqrt{11},; |\vec c \times \vec d| = 3$ and the angle between $\vec c$ and $\vec d$ is $\frac{\pi}{4}$. Then $\vec a \cdot \vec d$ is equal to:

Solution

$\vec c = 2\hat i + 2\hat k + \hat k = 2\hat i + 2\hat j + \hat k$

$|\vec c| = 3$

$|\vec c \times \vec d| = |\vec c||\vec d|\sin\frac{\pi}{4}$

$3 = 3|\vec d|\cdot \frac{1}{\sqrt{2}} \Rightarrow |\vec d| = \sqrt{2}$

$|\vec d - \vec a|^2 = |\vec d|^2 + |\vec a|^2 - 2\vec a\cdot\vec d$

$11 = 2 + 9 - 2\vec a\cdot\vec d$

$\Rightarrow \vec a\cdot\vec d = 0$

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