Aspire Faculty ID #4382 · Topic: NIMCET 2017 · Just now
NIMCET 2017

Consider the equation (40)x = (132)y is some bases x and y. Then a possible set of value of x and y are

Solution

$\begin{array}{ll}{{{(40})}_x={{(132)}}_y} \\ {\Rightarrow4\times{x}^1}+0\times{x}^0=1\times{y}^2+3\times{y}^1+2\times{y}^0 \\ {\Rightarrow4x+0={y}^2+3y^{}+2} \\ {4x={y}^2+3y^{}+2}\end{array}$

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Manmohan dwivedi
Manmohan dwivedi , Nimcet
Commented May 21, 2022
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Vinay
Vinay , Student
Commented Feb 28, 2021
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