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Question
A ball is thrown off the edge of a building at an angle of 60° and with an initial
velocity of 5 meters per second. The equation that represents the horizontal
distance of the ball x is x=ν0(cosθ)t, where ν0 is the initial velocity. θ is the
angle at which it is thrown and t is the time in seconds. About how far will the ball
travel in 10 seconds?
🎥 Video solution / Text Solution of this question is given below:
Horizontal Distance of Projectile
A ball is thrown at an angle of 60° with an initial velocity of 5 m/s. Calculate how far it will travel horizontally after 10 seconds.
x = v₀ × cos(θ) × t
Given:
v₀ = 5 m/s
θ = 60° (cos 60° = 0.5)
t = 10 s
x = 5 × 0.5 × 10 = 25 meters
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