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Given the equation: \( Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0 \)
Compute: \( \Delta = B^2 - 4AC \)
For the equation: \( 3x^2 + 10xy + 11y^2 + 14x + 12y + 5 = 0 \)
\( A = 3 \), \( B = 10 \), \( C = 11 \) → \( \Delta = 10^2 - 4(3)(11) = 100 - 132 = -32 \)
Since \( \Delta < 0 \), it represents an ellipse.
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